Thursday, September 17, 2009
Website for Solving Absolute Value Inequalities
http://algebralab.net/lessons/lesson.aspx?file=Algebra_AbsoluteValueInequalities.xml
Monday, September 14, 2009
Compound Inequalities
AND Compound Inequalities
Compound inequalities that contain the word and are true only if both inequalities are true. The graph of a compound inequality containing and is the intersection of the graphs of the two inequalities that make up the compound inequality. To find the intersection, determine where the two graphs overlap.
OR Compound Inequalities
Compound inequalities that contain the word or are true if one or more of the inequalities is true. The graph is the union of the graphs of the two inequalities that make up the compound inequality.
Wednesday, September 9, 2009
Inequality RULE
When multiplying or dividing both sides of an inequality by a negative number, you must reverse the inequality symbol.
Sunday, September 6, 2009
Example: Solve absolute value equations
Solve | 2x – 3 | – 4 = 3
First, I'll isolate the absolute-value part; that is, I'll get the absolute-value expression by itself on one side of the "equals" sign, with everything else on the other side:
| 2x – 3 | – 4 = 3
| 2x – 3 | = 7
Now I'll clear the absolute-value bars by splitting the equation into its two cases, one for each sign:
(2x – 3) = 7 or –(2x – 3) = 7
2x – 3 = 7 or –2x + 3 = 7
2x = 10 or –2x = 4
x = 5 or x = –2
So the solution is x = –2, 5.
First, I'll isolate the absolute-value part; that is, I'll get the absolute-value expression by itself on one side of the "equals" sign, with everything else on the other side:
| 2x – 3 | – 4 = 3
| 2x – 3 | = 7
Now I'll clear the absolute-value bars by splitting the equation into its two cases, one for each sign:
(2x – 3) = 7 or –(2x – 3) = 7
2x – 3 = 7 or –2x + 3 = 7
2x = 10 or –2x = 4
x = 5 or x = –2
So the solution is x = –2, 5.
Thursday, September 3, 2009
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